How do you calculate the trigonometric ratios of 30(degrees) and 60(degrees)?
Asked by smjaanu | 5th Apr, 2009, 07:05: AM
Consider equilateral triangle ABC. Drop perpendicular AD onto BC.
We know that the perpendicular will bisect the base( has been proved in earlier classes)
Angle BAD=30 degrees
So, In right triangle ABD
sin (Angle BAD)=sin 30 = opposite side / hypotenuse=BD/AB
Similarly , in the same triangle ratios of 60 degrees can be found.
(To find the length of AD , use pythagoras' theorem)
Answered by | 5th Apr, 2009, 09:06: AM
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