How do I solve the following??

Asked by  | 20th Feb, 2009, 09:44: PM

Expert Answer:

Let it be placed at a distance y from 4Q and x-y from 2Q.

or equilibrium we have:

k4Qq/(y2 )=k2Qq/(x-y)2

Hence, 2(x-y)2 =y2

y2 -4xy+2x2 =0

Hence ,y= x(4-2(2)0.5 )/2


Answered by  | 20th Feb, 2009, 11:48: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.