How do I derive the order of the reactant [Y] when there’s no instance in the given experiment where the concentration value for [X] is a constant ? 

Asked by astutijoshi | 23rd Jun, 2019, 08:44: PM

Expert Answer:

Order of reaction is a practical data so 
Order space of space reaction equals straight k left square bracket straight A right square bracket to the power of straight m left square bracket straight B right square bracket to the power of straight n
From space First space and space second space observation
fraction numerator 0.02 over denominator 0.02 end fraction equals fraction numerator left square bracket 0.1 right square bracket to the power of straight m space left square bracket 0.1 right square bracket to the power of straight n over denominator left square bracket 0.2 right square bracket to the power of straight m space left square bracket 0.1 right square bracket to the power of straight n end fraction

1 equals left parenthesis 1 half right parenthesis to the power of straight m
straight n equals 0

From space First space and space Third space observation

fraction numerator 0.02 over denominator 0.08 end fraction equals fraction numerator left square bracket 0.1 right square bracket to the power of 0 space left square bracket 0.1 right square bracket to the power of straight n over denominator left square bracket 0.3 right square bracket to the power of 0 space left square bracket 0.2 right square bracket to the power of straight n end fraction

1 fourth equals open parentheses 1 half close parentheses to the power of straight n
straight n equals 2
 
So order of the reactant [Y] is 2.

Answered by Ravi | 24th Jun, 2019, 12:39: PM

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