Histogram & Frequency Polygon

Asked by  | 7th Sep, 2008, 10:12: PM

Expert Answer:

Steps:

(1) Select the class interval withthe minimum class size. In our case it is 4.

(2) The length of the rectangles are then modified  to be proportionate to the class size.

for class size 4, the length of the rectangle will be = ((frequency)/ class size) x (minimum class size)

= (5/4) x 4 = 5

for class size 6, the length of the rectangle will be = ((frequency)/ class size) x (minimum class size)

= (6/6) x 4 = 4

for class size 12, the length of the rectangle will be = ((frequency)/ class size) x (minimum class size)

= (9/12) x 4 =3

for class size 20, the length of the rectangle will be = ((frequency)/ class size) x (minimum class size)

= (25/20) x 4 = 5

for class size 28, the length of the rectangle will be = ((frequency)/ class size) x (minimum class size)

= (21/28) x 4 = 3

Now draw the hisogram using the new table which is:

Class Interval 10-14 14-20 20-32 32-52 52-80
Frequency 5 6 9 25 21
Width of the class 4 6 12 20 28
height of rectangles 5 4 3 5 3

Answered by  | 13th Aug, 2014, 11:25: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.