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CBSE Class 10 Answered

hey it is a question of topper test but it was not clearly mentioned so please clearly give the ans.
Asked by | 02 Feb, 2010, 11:09: PM
answered-by-expert Expert Answer

Dear student,

When a total current  IP is passed through  parallel connected resistances R1 and R2, the voltage VP which appears across the parallel circuit is:
VP = IPRP = IPR1R2 / (R1 + R2)

The currents I1 and I2 which pass through  the respective resistances  R1 and R2 are:
I1 = VP / R1 = IPRP / R1 = IPR2 / (R1 + R2)
I2 = VP / R2 = IPRP / R2 = IPR1 / (R1 + R2)

Hence Assuming I2 to be the current passing through the 2 ohm resistor,

0.8 amps.

Hope this helps.

Regards

Topperlearning.com


Answered by | 02 Feb, 2010, 11:24: PM
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