CBSE Class 12-science Answered
Heptane and octane from ideal solution at 373k the vapour pressure of the two liquid components 105.2kpa and 46.8kpa respectivly if the solution contains 25g of Heptane and 35g of octane calculate 1.vapour pressure of heptane and octane 2.v.p.exerted by the solution 3.molefraction of octane in vapour phase
Asked by mayadesai | 06 Jul, 2013, 06:57: PM
Expert Answer
Vapour pressure of heptane
Vapour pressure of octane = 46.8 kPa
We know that,
Molar mass of heptane (C7H16) = 7 × 12 + 16 × 1
= 100 g mol?1
Number of moles of heptane =25/100
= 0.25 mol
Molar mass of octane (C8H18) = 8 × 12 + 18 × 1
= 114 g mol?1
Number of moles of octane
= 0.31 mol
Mole fraction of heptane,.25/(.25+.31)
= .448
And, mole fraction of octane, x2 = 1 ? 0.456
= 0.551
Now, partial pressure of heptane,
= 0.488 × 105.2
= 51.34 kPa
Partial pressure of octane,
= 0.551 × 46.8
= 25.79 kPa
Hence, vapour pressure of solution, ptotal = p1 + p2
= 77.13kPa
Answered by | 08 Jul, 2013, 01:01: AM
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