CBSE Class 12-science Answered
help
Asked by Rahulsinha1993 | 02 Nov, 2010, 11:36: PM
Expert Answer
Dear student,
Let the vector be ai+bj+ck
Given (ai+bj+ck).(i+j-3k)= 0
so a+b-3c=0 -----(1)
Given (ai+bj+ck).(i+3j-2k)= 0
so a+3b-2c=5 -----(2)
Given (ai+bj+ck).(2i+j+4k)= 0
so 2a+b+4c=8 -----(3)
Now solve equations (1) , (2) and (3) simultaneously
You may use the cramer's rule , and find values of a , b and c
a = 1, b= 2 , c= 1
We hope that clarifies your queries,
regards,
Team Topper Learning
Answered by | 04 Nov, 2010, 12:36: PM
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