help

Dear student,

 

Let the vector be ai+bj+ck

Given (ai+bj+ck).(i+j-3k)= 0

so a+b-3c=0  -----(1)

 

Given (ai+bj+ck).(i+3j-2k)= 0

so a+3b-2c=5  -----(2)

 

Given (ai+bj+ck).(2i+j+4k)= 0

so 2a+b+4c=8  -----(3)

 

Now solve equations (1) , (2) and (3) simultaneously

You may use the cramer's rule , and find values of a , b and c

 

a = 1, b= 2 , c= 1

 

We hope that clarifies your queries,

regards,

Team Topper Learning