help

Asked by Rahulsinha1993 | 2nd Nov, 2010, 11:36: PM

Expert Answer:

Dear student,
 
Let the vector be ai+bj+ck
Given (ai+bj+ck).(i+j-3k)= 0
so a+b-3c=0  -----(1)
 
Given (ai+bj+ck).(i+3j-2k)= 0
so a+3b-2c=5  -----(2)
 
Given (ai+bj+ck).(2i+j+4k)= 0
so 2a+b+4c=8  -----(3)
 
Now solve equations (1) , (2) and (3) simultaneously
You may use the cramer's rule , and find values of a , b and c
 
a = 1, b= 2 , c= 1
 
We hope that clarifies your queries,
regards,
Team Topper Learning

Answered by  | 4th Nov, 2010, 12:36: PM

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