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Asked by  | 20th Jan, 2009, 02:51: PM

Expert Answer:

The molecular formula of Ethanoic acid is CH3COOH.

The atomic number of C is 6 . So,its electronic configuration is 2,4. The valence electrons are 4.

The atomic number of H is 1 . So,its electronic configuration is 1. The valence electrons are 1.

The atomic number of O is 8 . So,its electronic configuration is 2,6. The valence electrons are 6.

So, its electron dot structure is as follows:

 

 

Answered by  | 21st Jan, 2009, 04:16: PM

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