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Asked by | 20th Jan, 2009, 02:51: PM
Expert Answer:
The molecular formula of Ethanoic acid is CH3COOH.
The atomic number of C is 6 . So,its electronic configuration is 2,4. The valence electrons are 4.
The atomic number of H is 1 . So,its electronic configuration is 1. The valence electrons are 1.
The atomic number of O is 8 . So,its electronic configuration is 2,6. The valence electrons are 6.
So, its electron dot structure is as follows:
Answered by | 21st Jan, 2009, 04:16: PM
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