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CBSE Class 10 Answered

help quickly
Asked by patshubhangi | 02 Mar, 2011, 04:12: AM
Expert Answer
Dear Student,
Here is the solution:
AP=13 cm
BP=3 cm
Therfore AB=10cm
 
Given MN bisects AB
Let MN bisect AB at E.
Therefore, AE = EB = 5cm
 
Also, In triangles AEM and AEN
AM=AN
AE=AE
angle AEM=angle AEN =90
Therefore ME = NE =x(say).........(i)
 
Now in triangle AEM
AM2 = ME2+AE2
132 = x2+52
x2= 132-52
x2= 144
x=12
 
from (i)
ME = EN=x
ME+EN=MN
or MN = x+x
MN=24 cm
 
 
Regards
Team Topperlearning
 
 
Answered by | 05 Mar, 2011, 06:09: PM
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