Help me to solve the problem..

Asked by nitishkrnehu09 | 18th Nov, 2017, 10:05: PM

Expert Answer:

Charge on the capacitor keep on decreasing as per the following equation
q = q0 exp { - t/ (RC) }
Let us assume at time T the charge is halved in the capacitor.
if we substitute q = q0/2 in the above equation we get 2 = exp{T/RC) after simplification.
Hence T = RC ln(2)


Answered by  | 20th Nov, 2017, 02:55: PM

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