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CBSE Class 11-science Answered

Help me to solve the following..
Asked by nitishkrnehu09 | 18 Nov, 2017, 09:28: PM
answered-by-expert Expert Answer
begin mathsize 16px style square root of straight x plus 3 minus 4 square root of straight x minus 1 end root end root plus square root of straight x plus 8 minus 6 square root of straight x minus 1 end root end root equals 1
Put space square root of straight x minus 1 end root equals straight t
rightwards double arrow straight x equals straight t squared plus 1
after space simplifying space it space you space will space get comma
square root of open parentheses straight t minus 2 close parentheses squared end root plus square root of open parentheses straight t minus 3 close parentheses squared end root equals 1
rightwards double arrow straight t minus 2 plus straight t minus 3 equals 1 space space space space space space space space OR space space space space space space space space minus left parenthesis straight t minus 2 right parenthesis minus open parentheses straight t minus 3 close parentheses equals 1
Hence comma space we space get space two space values space of space straight t
rightwards double arrow We space will space have space two space distinct space values space of space straight x. end style
Answered by Sneha shidid | 01 Dec, 2017, 05:49: PM

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