HELP! HELP! HELP!

Asked by  | 28th Dec, 2009, 07:02: PM

Expert Answer:

The permutations in which the four I's do come together are,

IIII*******, *IIII******, **IIII*****, ***IIII****, ****IIII***, *****IIII**, ******IIII*, *******IIII.

And they are 8 in number.

The total distinct permutation of the letters in the word are = 11!/(4!4!2!) = 34650

(We divide by 4! because I occurs 4 times, similary for S and 2! for P which repeats twice)

Hence the distinct permutation in which the four I's don't come together = 34650 - 8 = 34642

Regards,

Team,

TopperLearning.

Answered by  | 29th Dec, 2009, 01:23: AM

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