CBSE Class 11-science Answered
Hello.
Asked by akshay2703 | 09 Jul, 2009, 07:49: PM
Expert Answer
f(x+t) = 1/2 + [f(x) - f2(x)]
f(x+2t) = f((x+t)+t)
= 1/2 + [f(x+t) - f2(x+t)]
= 1/2 + {[1/2 + [f(x) - f2(x)]] - [1/2 + [f(x) - f2(x)]]2}
= 1/2 + {[1/2 + [f(x) - f2(x)]] - [1/4 + [f(x) - f2(x)] + f(x) - f2(x)]}
= 1/2 + {[1/2 + [f(x) - f2(x)] - 1/4 - [f(x) - f2(x)] - f(x) + f2(x)]}
= 1/2 + [1/4 - f(x) + f2(x)] ≠ f(x).
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Answered by | 21 Aug, 2009, 07:40: PM
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