CBSE Class 11-science Answered
hello sir,
Asked by | 24 Jan, 2009, 04:05: PM
Expert Answer
Use T = 2 pi (square root of L/g)
T1/T2 = (square root of L1)/square root of L2 = 11/10
So they will be in the same phase in 110 seconds which is the hcf of time period of the two pendulums.
Now you can find how many vibrations the shorter pendulum makes in 110s.
Answered by | 28 Jan, 2009, 02:40: PM
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