Hello sir, may i know please that how to write or find the equilibrium constant for the rxn -

Cu  _(s) + 2Ag⁺  ? Cu²⁺ + 2Ag  _(s).

K = [Active masses of products]  / [Active masses of reactants]

 

K = [Cu²⁺ ]      [ Ag  _(s) ] ²  /  [Cu ]_(s)  + [ Ag⁺  ]²           

SINCE THE ACTIVE MASSES OF SOLIDS IS TAKEN TO BE UNITY AS A CONVENTION

 

K = [Cu²⁺ ]       /    [ Ag⁺  ]²  

Now, we have G = - nFE⁰  

         and  G = -2.303 RT log K     Thus - nFE⁰ =   -2.303 RT log K 

For the reaction the n = 2 ( number of electrons exchanged)

 

so, 2 X 96500 X 0.46 V  = 2.303 x 8.313 x 298 log K

Now find the value of log K, the equilibrium constant