Hello sir, may i know please that how to write or find the equilibrium constant for the rxn -

Asked by Vishal Bharadwaj | 19th Jun, 2013, 12:30: PM

Expert Answer:

Cu  (s) + 2Ag+  ? Cu2+ + 2Ag  (s).
K = [Active masses of products]  / [Active masses of reactants]
 
K = [Cu2+ ]      [ Ag  (s) ] 2  /  [Cu ](s)  + [ Ag+  ]2           
SINCE THE ACTIVE MASSES OF SOLIDS IS TAKEN TO BE UNITY AS A CONVENTION
 
K = [Cu2+ ]       /    [ Ag+  ]2  
Now, we have G = - nFE0  
         and  G = -2.303 RT log K     Thus - nFE0 =   -2.303 RT log K 
For the reaction the n = 2 ( number of electrons exchanged)
 
so, 2 X 96500 X 0.46 V  = 2.303 x 8.313 x 298 log K
Now find the value of log K, the equilibrium constant
 
 
 
 
 
 
 
 
 
 
 
 
 

Answered by  | 19th Jun, 2013, 01:37: PM

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