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CBSE Class 10 Answered

heights and distances
Asked by | 03 Feb, 2010, 05:59: PM
answered-by-expert Expert Answer

 

 

tan θ = (H - h)/x

H = xtan θ + h .......(1)

Now,

tan Φ = h/x,

x = h/tan Φ

Put for x in (1),

H = (h/tan Φ) tan θ + h

= h((tan θ/tan Φ) + 1)

= h(tan θ cot Φ + 1)

Regards,

Team,

TopperLearning.

 

 

 

Answered by | 04 Feb, 2010, 09:44: AM

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