CBSE Class 10 Answered
heights and distances
Asked by Harshita Bhola | 26 Nov, 2010, 10:46: AM
Expert Answer
Dear Student,
To find: x
Given: AD = 300, and angles ACB and DCB are 600 and 450 respectively.
Solution: C is the point of observation on the ground
Now,
In triangle DCB,
Tan 45 = 1 = h/x
=> h = x…………………(1)
In triangle ACB,
Tan 60 = √3 = (h+300)/x
=> h+300 = √3 x
=> x+300 = √3x………………………..[from (1)]
=> (√3 - 1)x = 300
=> x = 300/(√3 - 1)
=> x = 409.8 m
Regards Topperlearning.
Answered by | 27 Nov, 2010, 10:16: AM
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