heights and distances
Asked by | 7th Feb, 2010, 04:10: PM
Let the speed of the jet plane be V in m/s and X be the initial horizontal distance of jet plane from the observer.
D, the distance it travels in 8 seconds = 8V.
tan 60 = 18003/X
or X = 18003/tan 60 = 1800 m
The horizontal distance, X increases by D = 8V in next 8 seconds and the angle of elevation becomes 45.
tan 45 = 18003/(X+8V)
X + 8V = 18003/tan 45 = 18003
8V = 1800x1.73 - X = 1800x0.73 = 1314 m
V = 1314/8 = 164.25 m/s
Answered by | 7th Feb, 2010, 04:34: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number