CBSE Class 10 Answered
heights and distances
Asked by | 29 Sep, 2008, 06:01: PM
Expert Answer
Let PQ be the tower and the height of the tower = h
Let the first point of observation be A . From A the angle of elevation is 32deg and let B be the second point of observation 100 mt closer to the tower be B . From B the angle of elevation is 63 deg
SoFrom triangle PAQ:
h/x = tan 63 = 1.9626
i.e h = 1.9626 x
Similarly from triangle PBQ
h / (100+x) = tan 32 = 0.6248
i.e 1.9626 x = 0/6248 (100+x)
(1.9626- .6248) x = 62.48
1.3378 x = 62.48
x = 62.48/ 1.3378
X= 46.70
See figure attached
Answered by | 30 Sep, 2008, 11:23: AM
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