height of observer 1.5m,distance 28.5m,height of tower 30m.find angle of elevation

Asked by  | 17th Sep, 2008, 01:04: PM

Expert Answer:

from eyes of observer the height of tower H = 30 - 1.5 = 28.5

and distance D = 28.5m

so angle of elevation = tan-1 ( H/D) = tan-1 (1) = 45o

Answered by  | 17th Sep, 2008, 05:52: PM

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