height and distances

Asked by debasish2345 | 15th Jul, 2009, 09:27: PM

Expert Answer:

 

AB is tree, AC is its vertical height(h) ,Dist CD =a
;Dist CE = b
In triangle ACD  also In triangle ACE
Tanα =h/a      tan β=h/b
a = h/tanα        b =h/tanβ
Now
(b-a) =h/tanα –h/tanβ
(b-a) = h(1/tanα -1/tanβ)…taking lcm
h =(b –a).tanα tanβ/tanα-tanβ

Answered by  | 18th Jul, 2009, 10:51: PM

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