Asked by baidshryans | 27th Dec, 2008, 01:08: PM
Let 'r' be the resistance of the electric kettle, v1= 22o v , t1 = 6.5 min , v2= 200 v , t2 = ?
As the heat produced in both the cases will be same ,
Use the relation,
heat produced = v12 t1 / r = v22 t2 / r
and plug in the values , to get the time t2, required if the supply had been 200V .
Answered by | 27th Dec, 2008, 09:10: PM
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