half life
Asked by | 21st Feb, 2010, 07:57: PM
Expert Answer:
It is given that disintegration rate to be proportional to the number of radioactive atoms in the sample.
So, [A]o = 4280 counts per min
[A] = 1070 counts per min
time is from 1:35 min to 4:55 min
So, 200 minutes
k = (2.303/t) log ( [A]o/ [A] )
k = (2.303/200) log(4280/1070)
= 0.127
t1/2 = 0.693/k = 0.693/ 0.127 = 5.45 min
Answered by | 24th Feb, 2010, 04:22: PM
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