half life of a reaction

Asked by  | 4th Jun, 2009, 02:10: AM

Expert Answer:

Q 1. t = 2.303/k log ([Ro]/[R])

 = (2.303 / 7.4 x 10-5) log 100/25

= 0.187 x 10 5 min

Q 2.

(a) k  = 1/37.9 = 0.026

t = 2.303 / 0.026 * .6021 = 53.33 min

(b) 1 = 2.303/ 0.026 log [R0] / [R]

[R0] / [R] = 1.288

a/(a-x) = 2.88

If a  = 100,

x = 21.8

 

 

Answered by  | 29th Jun, 2009, 05:05: PM

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