half life of a reaction
Asked by | 4th Jun, 2009, 02:10: AM
Expert Answer:
Q 1. t = 2.303/k log ([Ro]/[R])
= (2.303 / 7.4 x 10-5) log 100/25
= 0.187 x 10 5 min
Q 2.
(a) k = 1/37.9 = 0.026
t = 2.303 / 0.026 * .6021 = 53.33 min
(b) 1 = 2.303/ 0.026 log [R0] / [R]
[R0] / [R] = 1.288
a/(a-x) = 2.88
If a = 100,
x = 21.8
Answered by | 29th Jun, 2009, 05:05: PM
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