Haemoglobin contains 0.33% of iron by weight. Molecular weight of haemoglobin is approximately 67200. How many iron atoms are present in molecule of Haemoglobin

Asked by Anil | 11th May, 2017, 11:58: AM

Expert Answer:

Percentage of Fe = 0.33% molecular weight of haemoglobin

Weight of Fe present = (0.33/100) × 67200 = 221.8

one Fe weighs 55.8 g

Therefore, 221.8/55.8 = 4

Hence, 4 atoms of iron are present in one molecule of haemoglobin.

Answered by Vaibhav Chavan | 11th May, 2017, 04:15: PM