haarshit ..........triangles.........................???///

Asked by  | 19th Feb, 2009, 06:02: PM

Expert Answer:

in triangle ACD ,tanA =CD/AD...(1)
in triangle BCD ,tanB =CD/BD...(2)
Dividing above two eqn,we get:
tanB/tanA=AD/BD=(AC/BC)/(BC/AC)=(AC/BC)2



Answered by  | 20th Feb, 2009, 12:43: AM

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