haarshit ..........triangles.........................???///
Asked by | 19th Feb, 2009, 06:02: PM
Expert Answer:
in triangle ACD ,tanA =CD/AD...(1)
in triangle BCD ,tanB =CD/BD...(2)
Dividing above two eqn,we get:
tanB/tanA=AD/BD=(AC/BC)/(BC/AC)=(AC/BC)2
Answered by | 20th Feb, 2009, 12:43: AM
Related Videos
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change