Given is AB the diameter of circle and CD is a chord equal to the radius of the circle. AC & BD when extended intersect at a point E.Then Prove that Angle AEB = 60.
Asked by singhaivk05 | 25th Feb, 2015, 05:33: PM
Answered by Vimala Ramamurthy | 26th Feb, 2015, 10:57: AM
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