Given 18M H2SO4 solution with density 1.96 g per ml find Molality

Asked by Mudita Agrawal | 12th Sep, 2013, 09:57: PM

Expert Answer:

18 M solution means that 18 moles of H2SO4 are present in 1 L solution.

Mass of H2SO4 in 1 L solution = 18 ×98=1764g (Since Molecular mass of H2SO4 = 98)

Density of solution = 1.96 gmL-1

Mass of 1L solution = 1000×1.96=1960g

Mass of water in solution =1960-1764=196g

Molality = Moles of solute   ×   1000

                 Mass of solvent (in g)

               = 18   × 1000

                  196

              =91.8m

 

Answered by Vaibhav Chavan | 13th Sep, 2013, 11:05: AM

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