give the derivation of zero order.
Asked by | 13th May, 2013, 10:35: PM
Expert Answer:
For zero order reaction, the rate law is :
Rate=?d[A]/dt = k[A]0 = k = constant
Lets take a general reaction:
A -> P
If it is a reaction of zero order then we can write,
Rate = -d [A] / dt = k [A] 0 = k
or, d [A] = k dt
Integrating both sides, we will get:
[A] = kt + I
Where I is a constant of integration
At, t = 0, [A] = [A] 0
Therefore, [A] 0 = I
Substituting this value of I in equation 1, we will get:
[A] = -kt + [A] 0
kt = [A] 0 [A]
k = 1 / t ([A] 0 [A])
Hence, the Integrated Rate Expression of Zero Order Reaction is
1 / t ([A] 0 [A])
A -> P
Rate = -d [A] / dt = k [A] 0 = k
or, d [A] = k dt
Integrating both sides, we will get:
[A] = kt + I
Where I is a constant of integration
At, t = 0, [A] = [A] 0
Therefore, [A] 0 = I
Substituting this value of I in equation 1, we will get:
[A] = -kt + [A] 0
kt = [A] 0 [A]
k = 1 / t ([A] 0 [A])
Hence, the Integrated Rate Expression of Zero Order Reaction is
Answered by | 14th May, 2013, 10:49: AM
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