CBSE Class 10 Answered
give the derivation of resultant power in series and parallel
Asked by rishabh trehan | 16 May, 2013, 07:09: PM
Expert Answer
P = I^2 * R or V^2/R
For a series connection with resistors R1, R2, R3...etc connected in series
R = R1+R2+R3+ ....
And the current in this circuit remains constant,
so, P = I^2 ( R1+R2+R3+ ....)
For a parallel connection with resistors R1, R2, R3...etc connected in parallel
1/R = 1/R1+1/R2+1/R3+ ....
And the voltage drop in this circuit remains constant,
so, P = V^2 /( 1/R1+1/R2+1/R3+ ....)
Answered by | 16 May, 2013, 09:31: PM
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