give the derivation of resultant power in series and parallel

Asked by rishabh trehan | 16th May, 2013, 07:09: PM

Expert Answer:

P = I^2 * R or V^2/R
 
For a series connection with resistors R1, R2, R3...etc connected in series
R = R1+R2+R3+ ....
And the current in this circuit remains constant, 
so, P = I^2 ( R1+R2+R3+ ....)
 
For a parallel connection with resistors R1, R2, R3...etc connected in parallel
1/R = 1/R1+1/R2+1/R3+ ....
And the voltage drop in this circuit remains constant, 
so, P = V^2 /( 1/R1+1/R2+1/R3+ ....)

Answered by  | 16th May, 2013, 09:31: PM

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