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Asked by as23072000 | 18 Sep, 2021, 07:12: AM
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Radius of curvature of mirror , R = 10 cm 
 
Focal length f = 5 cm
 
wire is placed at u = 20 cm
 
we have mirror equation , ( 1/v) + (1/u) = 1/f 
 
where v is mirror-to-image distance 
 
1/v = (1/5) - (1/20) = 3/20 
 
Hence , mirror to image distance = (20/3) cm = 6.67 cm
 
Magnitude of magnification = v/u = (20/3) / 20  = (1/3) 
 
If the plane of L-shaped wire is facing the mirror directly , then magnification of vertical side and horizontal side is same.
In that case , image size of horizontal side and that of verical side is same.
 
Image size is (1/3) of size of either vertical or horizontal length of wire .
Answered by Thiyagarajan K | 18 Sep, 2021, 08:14: AM
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