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Asked by poojathally | 18th Feb, 2010, 02:35: PM
AF = AE, BD = BF CD = CE, AB = AC
So, AB – AF = AC – AE , i.e BF = CE , i.e BD = CD
Hence BC is bisected at D , the point of contact
Answered by | 18th Feb, 2010, 03:03: PM
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