General Question
Asked by anubhav57 | 25th Feb, 2009, 01:29: AM
First and foremost is to remember the rules of logarithms.
When you are taking product of two numbers, use
log(mn) = log m +log n
if you are seeing the log of say 268.3, then you need to write 268.3as 2.683*100
100 is the second power of 10.
So you see the log of 2683 in the table and write it after 2.
So log(268.3)=2.4286
So you have seent that the power of 10 is of importance here.
when you have to see the antilog after using the formula,
remember that the decimal part of the number for which you are seeing the antilog must be positive.If it's not, then you need to make it positive.
e.g. for seeing antilog(-1.723)
write
-1.723
=-1+(-0.723)
=-1+ (-1+1-0.723)
= -2+0.277
now see the antilogtable entry for .27 under the column 7
that wil come out to be 1892
Since the integral part is -2, (a negative number )
we follow the rule that there will be one zero (2-1=1) after the decimal point and then the antilog entry.
So antilog(-1.723)=0.01892
Next, if the integral part of the number for which we have to see the antilog, is positve, then the number of places after the decimaal point will be integral part +1
e.g.
antilog(2.321)
here the decimal part is 2 which is non -negative.
So,
in the antilog entry 2094, we will leave 3 places(2+1=3) from the left and put the decimal point.
So,
antilog(2.321)=209.4
If you have any more doubts on this, do send.
Also any particular calculations need to be checked, you can send it , we will solve it for you.
Answered by | 25th Feb, 2009, 10:19: AM
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