CBSE Class 11-science Answered
functions
Asked by | 04 Oct, 2009, 12:22: PM
Expert Answer
Given f(x)= 3x-5/2x+5
For f -1 to exists f must be one -one and onto
f is one-one
Let f(x1)=f(x2)
(3x1-5) /(2x1+5) = (3x2-5)/(2x2+5)
(3x1-5)(2x2+5)=(3x2-5)(2x1+5)
6x1x2+15x1-10x2-25=6x1x2+15x2-10x1-25
So x1 = x2
so f is one-one.
Let y be a real number
s.t f(x)=y
3x-5/2x+5 =y
x = 5y+5/(3-2y)
which is defined for all y except 3/2
so f-1 = 5x+5/(3-2x)
Answered by | 05 Oct, 2009, 10:30: AM
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