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CBSE Class 10 Answered

frustum is formed from a cone of height h by removing a cone of height 1/3h .ratio of radii of its ends are?
Asked by parmodgulati | 08 Jan, 2014, 10:57: AM
answered-by-expert Expert Answer
Consider the following figure.
The height of the cone is h units and the height of the removed cone is h/3 units.
 
Let r be the radius of one end and R be the radius of the other end.
 
Thus, CEGF is the frustum formed.
 
Consider the triangles ABC and ADE.
 
Since , we have .
Therefore, the corresponding sides are proportional.
 
Thus, we have,
 
Therefore, we have
 
Answered by Vimala Ramamurthy | 08 Jan, 2014, 02:27: PM

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