frustum is formed from a cone of height h by removing a cone of height 1/3h .ratio of radii of its ends are?
Asked by parmodgulati | 8th Jan, 2014, 10:57: AM
Consider the following figure.
The height of the cone is h units and the height of the removed cone is h/3 units.
Let r be the radius of one end and R be the radius of the other end.
Thus, CEGF is the frustum formed.
Consider the triangles ABC and ADE.
Since , we have .
Therefore, the corresponding sides are proportional.
Thus, we have,
Therefore, we have
Answered by Vimala Ramamurthy | 8th Jan, 2014, 02:27: PM
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