frustum is formed from a cone of height h by removing a cone of height 1/3h .ratio of radii of its ends are?

Consider the following figure.

The height of the cone is h units and the height of the removed cone is h/3 units.

 

Let r be the radius of one end and R be the radius of the other end.

 

Thus, CEGF is the frustum formed.

 

Consider the triangles ABC and ADE.

 

Since , we have .

Therefore, the corresponding sides are proportional.

 

Thus, we have,

 

Therefore, we have