Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 10 Answered

from units TRIANGLES
Asked by | 09 Mar, 2009, 11:35: PM
answered-by-expert Expert Answer

Draw the diagram as mentioned in the question.

Let CD be theperpendicular from C to AB.

Acc to question,

AB=c,BC=a, AB=c,CD=p

CAB is a right triangle and so is DCB.

angle BDC= angle BCA( each is 90 )

angle DBC= angle ABC(common angle to both triangles)

So,

 triangle DCB similar to triangle CAB(AA rule)

DC/CA=CB/AB( corr sides of similar trianglesaa re proportional)

p/b=a/c

1/p=c/ab

squaring both sides,

solving one step further we get the answer.

 

Answered by | 10 Mar, 2009, 12:51: PM
CBSE 10 - Maths
Asked by tejasdd | 28 May, 2010, 08:18: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by ketanvai | 23 Apr, 2010, 06:35: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by srprusty | 10 Apr, 2010, 05:43: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by s.sreeram | 11 Mar, 2010, 08:14: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by | 10 Mar, 2010, 07:26: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by rinki94 | 10 Mar, 2010, 03:59: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:24: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:08: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:05: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by nishac | 10 Mar, 2010, 09:12: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×