FRom the top of the tower 100 m in height a ball is dropped and the same time another ball is projected vertically upwards from the ground with the velocity of 25 m/s.From when and where the 2 balls will meet ? ( g = 9.8 m/s2 )

Asked by nisha_vini29 | 6th Jul, 2017, 11:48: AM

Expert Answer:

begin mathsize 12px style Let space the space two space balls space meet space at space straight a space distance space straight h space from space the space top space of space the space tower space after space straight t space seconds. We space use space the space equation space straight h space equals space 1 half space at squared space equals space 4.9 space straight t squared and space left parenthesis 100 space minus straight h right parenthesis space equals space 25 straight t space minus space 4.9 space straight t squared or space 100 space equals space 25 straight t rightwards arrow space straight t space equals 4 space straight s and space straight h space equals 1 half space cross times space 9.8 space cross times space 16 space space equals space 78.4 space straight m Thus comma space the space two space balls space meet space at space straight a space distance space 78.4 space straight m space from space the space top space of space the space tower space after space 4 space seconds. space end style

Answered by Yashvanti Jain | 6th Jul, 2017, 12:55: PM

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