CBSE Class 9 Answered
from chapter circles
Asked by ridhisood | 22 Feb, 2010, 06:58: PM
Expert Answer
let ABCD be the trapezium such that AB II CD
we have to prove that
if AD=BC, then ABCD is cyclic.
construction:draw a line thru' C parallel to AD meeting AB in E.
then AECD is a parallelogram... as both pairs of opp sides are parallel.
angle ADC=angle AEC.....(i).. opp angles of a parallelogram
now, AD=BC.... given
AD=CE... opp sides of II gram
so,
CE=BC
So,
angle CEB=angle CBE
but
angle CEA+CEB=180... linear pair
so
angle CBE+CEA=180
so from (i) we get,
angle CDA+CBE=180
i.e.
angle CDA+CBA=180
so quad ABCD is cyclic as one pair of opp angles is supplementary.
Answered by | 25 Feb, 2010, 04:43: PM
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