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CBSE Class 11-science Answered

<div>From a fixed support two small isentical spheres are suspended by means of strings of length 1m. THe two strings are pulled aside such that string 1 makes an angle of 30 degrees with the vertical and string 2 makes an angle of 6o degrees and then are released.Point "O" is given to be the mean position.Then the two spheres collide</div> <div>a)at 'O' after 0.25s</div> <div>b)at 'O'after 0.25s</div> <div>c)on the right of 'O' after some time</div> <div>d)on the right hand side of 'O' when the strings are inclined at 15 degrees with the vertical.</div>
Asked by Malavika Umesh | 26 Apr, 2015, 07:33: PM
Expert Answer
The time taken by both the spheres to travel the distance so as to collide is given as:
begin mathsize 12px style straight t space equals space straight T over 4 We space know space that space straight T space equals space 2 straight pi square root of straight l over straight g end root rightwards arrow straight t space equals space 1 fourth space cross times space 2 straight pi square root of straight l over straight g end root space space space space space space equals fraction numerator 2 cross times 3.14 over denominator 4 end fraction space cross times square root of 1 over 10 end root space tilde space 0.5 space straight s end style
 
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Answered by Yashvanti Jain | 13 Dec, 2017, 06:34: PM

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