From a fixed support two small isentical spheres are suspended by means of strings of length 1m. THe two strings are pulled aside such that string 1 makes an angle of 30 degrees with the vertical and string 2 makes an angle of 6o degrees and then are released.Point "O" is given to be the mean position.Then the two spheres collide
a)at 'O' after 0.25s
b)at 'O'after 0.25s
c)on the right of 'O' after some time
d)on the right hand side of 'O' when the strings are inclined at 15 degrees with the vertical.

Asked by Malavika Umesh | 26th Apr, 2015, 07:33: PM

Expert Answer:

The time taken by both the spheres to travel the distance so as to collide is given as:
begin mathsize 12px style straight t space equals space straight T over 4 We space know space that space straight T space equals space 2 straight pi square root of straight l over straight g end root rightwards arrow straight t space equals space 1 fourth space cross times space 2 straight pi square root of straight l over straight g end root space space space space space space equals fraction numerator 2 cross times 3.14 over denominator 4 end fraction space cross times square root of 1 over 10 end root space tilde space 0.5 space straight s end style
 
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Answered by Yashvanti Jain | 13th Dec, 2017, 06:34: PM