four resistors of four ohm each are connected in parallel , four such combination are then connected in series. what will be the total resistance?
Asked by sharmishtha rath | 13th Jun, 2013, 02:41: PM
We can first simplify the circuit to find the equivalent resistance in the circuit.
First considering, 4 resistances of 4 ohms each connected in parallel.
1/R'= 1/R1 + 1/R2+ 1/R3+1/R4 = 4* 1/4 = 1
R' = 1 ohm
Now, four such blocks of resistances are connected in series
Hence, R" = R' + R' + R' +R' = 4* R' = 4 ohms
Hence total resisance in the circuit is 4 ohms.
Answered by | 13th Jun, 2013, 04:34: PM
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