Four cells eac h of emf 1.9 V and internal resistance 1 ohm are connected to an external resistance of 18 ohm as shown in the fig. FInd the terminal potential difference of this combination.
Asked by kumar.ashlesha
| 16th Jun, 2015,
11:46: AM
Expert Answer:
Four cells each of emf 1.9 V and internal resistance 1 ohm
E= 1.9 V
r=1 Ω
Hence, the circuit becomes
Total internal resistance of the cell in a row
r'=1+1=2 Ω
Total resistance of the circuit,
R'=R+r'
R'=18+2=20 Ω
Therefore, the current in the circuit,
Hence, P.D should be 3.42 V according to given conditions.
Answered by Priyanka Kumbhar
| 17th Jun, 2015,
10:38: AM
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