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ICSE Class 10 Answered

Force of 0.8 gf acts  on a glass ball of mass 250 gram for 10 seconds if initially the ball is moving with a velocity of 50 cm per second find final velocity and distance covered  by ball

Asked by Samrat | 30 Jun, 2018, 09:35: PM
Expert Answer
acceleration produced by .8gf on 250 gram mass = force / mass = (0.8×10-3 ×9.8) / (250×10-3 ) = 3.136×10-2 m/s2
 
distance travelled in 10 s ,  S = u×t+(1/2)×a×t2  = 50×10-2 ×10 + (1/2)×3.136×10-2 ×10×10 = 6.568 m
 
final speed v = u + a×t = 50×10-2 + 3.136×10-2 ×10 = 81.36 cm/s
Answered by Thiyagarajan K | 01 Jul, 2018, 05:03: PM
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