For what value of k the equation ----------------has real and equal roots?

Dear student,

 

Here, a = 4, b = -2(k+1), c = k+1

 

D= b² - 4ac = 4(k+1)² -16(k+1)

 

The given equation will have real and equal roots if D = 0.

Therefore,  4(k+1)² -16(k+1) = 0

4(k+1) [k+1-4]=0

k+1 = 0 or k-3 = 0

Thus, k = -1 or k = 3

 

We hope that clarifies your query.

 

Regards,
Team

TopperLearning