For what value of k the equation ----------------has real and equal roots?

Asked by maitreyi mishra | 20th Mar, 2011, 04:24: AM

Expert Answer:

Dear student,
 
Here, a = 4, b = -2(k+1), c = k+1
 
D= b2 - 4ac = 4(k+1)2 -16(k+1)
 
The given equation will have real and equal roots if D = 0.
Therefore,  4(k+1)2 -16(k+1) = 0
4(k+1) [k+1-4]=0
k+1 = 0 or k-3 = 0
Thus, k = -1 or k = 3
 
We hope that clarifies your query.
 
Regards,
Team
TopperLearning

Answered by  | 19th Mar, 2011, 10:48: PM

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