For what value of k, A=(3,2),B=(_1,_k),c=(_3,_2),d=(1,2) vertices of parallelogram

Asked by rohithmannu46 | 17th Dec, 2019, 09:42: PM

Expert Answer:

ABCD is a parallelogram.
AB = CD
A = (3, 2),B = (-1, -k),C =(-3, -2),d = (1, 2)
AB2 = CD2 
(-3 - 1)2 + (2 + k)2 = (-3 - 1)2 + (-2 - 2)2
16 + 4 + 4k + k2 = 16 + 16
k2 + 4k - 12 = 0
(k + 6)(k - 2) = 0
k = -6 or k = 2

Answered by Sneha shidid | 18th Dec, 2019, 09:47: AM