for what angle horizontal projection is maximum a)90 degree (b) 45 degree (c) 60 degree (d) 0 degr

Asked by ritamkumar | 8th Nov, 2009, 05:49: AM

Expert Answer:

Horizontal range , X = vo2 sin 2 θ / g

From above eqn , it is clear that horizonatal range depends on the value of velocity of projection and angle of projection. For fixed vo , range will be maximum if sin 2 θ is max. i.e.

sin 2 θ = 1 = sin 90o

or, 2 θ = 90o

or, θ = 45o

Answered by  | 8th Nov, 2009, 01:45: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.