For very small angle of projection "a" with horizontal the ratio of RANGE to MAX.HEIGHT of a particle projected upwards with initial speed "u" from ground is ??

Asked by d.beckham | 6th Jun, 2011, 12:00: AM

Expert Answer:

As we know that
 
Range of the projectile, R = u2 sin2a / g
 
Max. Height, H = u2 sin2a / 2g
 
R / H = 2 sin2a / sin2a
 
For small angle, sin a = a 
 
R / H = (2 x 2a) / (a x a)
         = 4 / a

Answered by  | 6th Jun, 2011, 12:55: PM

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