CBSE Class 11-science Answered
For very small angle of projection "a" with horizontal the ratio of RANGE to MAX.HEIGHT of a particle projected upwards with initial speed "u" from ground is ??
Asked by d.beckham | 06 Jun, 2011, 12:00: AM
Expert Answer
As we know that
Range of the projectile, R = u2 sin2a / g
Max. Height, H = u2 sin2a / 2g
R / H = 2 sin2a / sin2a
For small angle, sin a = a
R / H = (2 x 2a) / (a x a)
= 4 / a
Answered by | 06 Jun, 2011, 12:55: PM
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