For two nos. a and b the LCM is L and the HCF is H. So L must be a multiple of H---True or false?if so how?
Asked by rittwik | 11th Sep, 2010, 07:19: PM
L must be a multiple of H.
From the definition of HCF, H divides both A and B. Also, from the definition of LCM, A and B both divide L.
So, H in turn divides L. Therefore, L is a multiple of H. (By Euclid's division lemma)
Answered by | 12th Sep, 2010, 12:31: AM
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