For the given figure, prove that AE is parallel to BD.
Asked by Topperlearning User | 5th Aug, 2014, 11:32: AM
In the above figure,
AE and BD are two lines cut by a transversal FC.
Also, the given angles are interior angles on the same side of the transversal.
Thus, in order to prove AE||BD, we have to check whether
AOP + BPO = 180o
(According to the property- "when a transversal cuts two lines, such that pairs of interior angles on the same side of the transversal are supplementary, then the lines have to be parallel")
AOP + BPO = 75o + 100o
= 175o 180o
Thus, AE is not parallel to BD.
Answered by | 5th Aug, 2014, 01:32: PM
- In the figure below, if AE||BD, then find the value of x:
- In the given figure, if BF||CE, find the value of x.
- In the given figure, find the value of y.
- Find the value of x, y and z in the figure given below.
- In the figure given below, WT||PS and VQ||UR. Find the values of angles a and b.
- In the figure below, AP is parallel to CD. The size w of angle PAB is equal to 135o and the size z of angle DCB is equal to 147o. Find angle ABC.
- In the figure given below, AL||EM. Find the measure of all the interior angles cut by the transversals PK and BN.
- Find the value of x and y in the figure given below:
- In the quadrilateral given below, SR||PQ. SP and RQ are the pair of transversals cutting SR and PQ. Find PSR and RQP.
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number