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NEET Class neet Answered

For linear simple harmonic motion with a given ω, two initial conditions are necessary and sufficient to determine the motion completely. The initial conditions may be (1) initial position and initial velocity or (2) amplitude and phast or (3) energy and phase.
Asked by anurag04823 | 12 Jan, 2023, 11:48: PM
answered-by-expert Expert Answer
Displacement of linear simple harmonic motion is
 
begin mathsize 14px style x space equals space A space sin left parenthesis omega t space plus space ϕ right parenthesis end style  ....................................(1)
 
where x is displacement , A is amplitude of oscillation , ω is angular frequency and Φ is initial phase.
 
There are three parameters to describe the motion of SHM , i.e., Amplitude A , angular frequncy ω and
Initial phase Φ.
 
Since angular frequency ω is given , we need two equations to get other two parameters.
 
----------------------------
 
(1) initial position and initial velocity are known .
 
Initial position xo is obtained by substituting t = 0 in eqn.(1).
 
xo = A sin Φ  ................................(2)
 
velocity of motion is determined by differentiating eqn.(1)
 
begin mathsize 14px style v space equals space fraction numerator d x over denominator d t end fraction space equals space A space omega space cos open parentheses omega t space plus space ϕ close parentheses end style  ................................(3)
 
Initial velocity vo is obtained by substituting t = 0 in eqn.(3).
 
vo = A ω cosΦ   .....................................(4)
 
By dividing eqn.(2) by eqn.(4) , we get
 
begin mathsize 14px style tan ϕ space equals space fraction numerator x subscript o over denominator v subscript o omega end fraction end style
Hence from above relation , we get initial phase Φ .
 
Then, using initial phase Φ , we get amplitude A either from eqn.(2) or eqn.(4) .
 
Hence by knowing Amplitude A and initial phase Φ , we can use eqn.(1) to get displacement as a function of time.
 
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(2) Amplitude and initial phase are known 
 
By knowing Amplitude A and initial phase Φ , we can use eqn.(1) to get displacement as a function of time.
 
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(3) Total energy and initial phase are known
 
Total energy U = (1/2) k A2
 
where k = begin mathsize 14px style square root of omega over m end root end style is force constant  and m is mass of particle that is undergoing SHM.
From above expression, we get amplitude A from known mass m and known angular frequency ω .
 
By knowing Amplitude A and initial phase Φ , we can use eqn.(1) to get displacement as a function of time.



 




 
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