For hydrogen atom the energy of a photon emitted during a transition from n=2 state to n=1 state is 

Asked by arushidabhade | 8th Jul, 2019, 08:07: PM

Expert Answer:

Given:
 
n1 =1
 
n2 = 2
 
RH = 2.18×10-18 J
 
We have,
 
increment straight E space equals space straight R subscript straight H straight Z squared space open square brackets fraction numerator 1 over denominator straight n subscript 1 superscript 2 end fraction minus fraction numerator 1 over denominator straight n subscript 2 superscript 2 end fraction close square brackets

space space space space space space space equals 2.18 cross times 10 to the power of negative 18 end exponent space open square brackets 1 over 1 minus 1 over 2 squared close square brackets

space space space space space space equals space 2.18 cross times 10 to the power of negative 18 end exponent cross times open square brackets fraction numerator 4 minus 1 over denominator 4 end fraction close square brackets

space space space space space space equals 1.635 space cross times 10 to the power of negative 18 end exponent space straight J
 
 

Answered by Varsha | 9th Jul, 2019, 12:06: PM